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ee.Image.leftShift
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针对 image1 和 image2 中每个匹配的波段对，计算 v1 左移 v2 位后的结果。如果 image1 或 image2 只有一个波段，则会将其与另一张图片中的所有波段进行比较。如果图片具有相同数量的波段，但名称不同，则会按自然顺序成对使用。输出波段的命名方式为：如果两个输入的长度不同，则以较长的输入命名；如果长度相同，则以 image1 的顺序命名。输出像素的类型是输入类型的并集。
| 用法 | 返回 |
|---|
Image.leftShift(image2) | 图片 |
| 参数 | 类型 | 详细信息 |
|---|
此：image1 | 图片 | 从中获取左操作数波段的映像。 |
image2 | 图片 | 从中获取右操作数波段的映像。 |
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最后更新时间 (UTC)：2025-07-26。
[null,null,["最后更新时间 (UTC)：2025-07-26。"],[[["\u003cp\u003eCalculates the left bitwise shift of corresponding bands in two images, using all bands or matching bands as appropriate.\u003c/p\u003e\n"],["\u003cp\u003eOutput image bands inherit the names of the longer input, or the first image's band names if they're equal in length.\u003c/p\u003e\n"],["\u003cp\u003ePixel type in the resulting image is determined by the most expressive type encompassing both input image types.\u003c/p\u003e\n"],["\u003cp\u003eThe function takes two image arguments, with the first image used as the base for the operation.\u003c/p\u003e\n"],["\u003cp\u003eIt's accessible via the \u003ccode\u003eImage.leftShift()\u003c/code\u003e method and produces a new Image as the result.\u003c/p\u003e\n"]]],["Performs a bitwise left shift operation between two images. It shifts the bits of `image1` by the amount specified in `image2` for each corresponding band. If one image has a single band, it's applied against all bands of the other. Bands are matched pairwise if they have the same number, otherwise the natural order. The output band names are derived from the longer input image or from `image1` if lengths are equal, and the output pixel type is a union of the inputs.\n"],null,["# ee.Image.leftShift\n\nCalculates the left shift of v1 by v2 bits for each matched pair of bands in image1 and image2. If either image1 or image2 has only 1 band, then it is used against all the bands in the other image. If the images have the same number of bands, but not the same names, they're used pairwise in the natural order. The output bands are named for the longer of the two inputs, or if they're equal in length, in image1's order. The type of the output pixels is the union of the input types.\n\n\u003cbr /\u003e\n\n| Usage | Returns |\n|---------------------------|---------|\n| Image.leftShift`(image2)` | Image |\n\n| Argument | Type | Details |\n|----------------|-------|---------------------------------------------------------|\n| this: `image1` | Image | The image from which the left operand bands are taken. |\n| `image2` | Image | The image from which the right operand bands are taken. |"]]
